Solve for x √3x 22√2x2√3=0 = 0 Solution Question 5 A two digit number is four times the sum of the digits It is also equal to 3 times the product of digits Find the number Solution Question 6 Solve for x√3x 2 – 2√2x2√3=0 Solution Question 7 Solve for x Solution Short Answer Type Questions II 3 Marks Question 8 Solve for xFind the roots of the following equations, if they exist, by applying the quadratic formula 2√3x^2 5x √3 = 0Share It On Facebook Twitter Email 1 Answer 1 vote answered 3 days ago by Ankush01 (77k points) selected 2 days ago by Devakumari Best answer The given equations is 2√3x 2 5x √3 = 0 Comparing
Completing The Square
X-3(2+3x)=2(5x-3)
X-3(2+3x)=2(5x-3)-C = 7√3 = √37√3 = 21 (using 3 = √3×√3) And either of their sum or difference = b = 10 Thus, the two terms are 7 and 3 Sum = 7 3 = 102√3x^2 5x √3 what is the simplification of this Answers 1 Show answers Another question on Math Math, 1400 The sum of 3rd and 15th term of an arithmetic progression is equal to the sum of 6th, 11th and 13th elements ofthe same progression then which term of the series should necessarily be equal to zero?
Solve 3x 2 5x 2 0 By Completing The Square Method
Click here 👆 to get an answer to your question ️ 2√3x^25x√3 factories it hiteshkr4 hiteshkr4 Math Secondary School 2√3x^25x√3 factories it 1 See answer hiteshkr4 is waiting for your help Add your answer and earn pointsCevap 2 Show answer Math, 0600 Points a2√3x 2 5x √3 = 0 quadratic equations;
√3x 2 10x 7√3 = 0 Answer Using the splitting middle term the middle term of the general equation is divided in two such values that Product = ac For the given equation a = √3 ;b = 10; selectedby Vikash Kumar Best answer 2√3x2˗ 5x √3 ⇒ 2√3x2˗ 2x ˗ 3x √3 ⇒ 2x (√3x ˗ 1) ˗ √3 (√3x ˗ 1) = 0 ⇒ (√3x ˗ 1) or (2x − √3) = 0 ⇒ (√3x ˗ 1) = 0 or (2x − √3) = 0 ⇒ x = 1/ √3 or x = √3/ 2 ⇒ x = 1/ √3 × √3 /√3 = √3/ 3 or x = √3/ 2 Best answer 2√3x2 ˗ 5x √3 ⇒ 2√3x2 ˗ 2x ˗ 3x √3 ⇒ 2x (√3x ˗ 1) ˗ √3 (√3x ˗ 1) = 0 ⇒ (√3x ˗ 1) or (2x − √3) = 0 ⇒ (√3x ˗ 1) = 0 or (2x − √3) = 0 ⇒ x = 1 3 or x = 3 2 ⇒ x = 1 3 x 3 3 = 3 3 or x = 3 2
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Incoming Term: x-3(2+3x)=2(5x-3), 2 root 3x^2-5x+root 3, 3x-2(5x+3)=14-2x, 3x^2-5x+3=0, 3x^2+5x-3 factored, 2^(x-3)=3x^2-5x+6), 2x^2+3x-7=x^2+5x+39, x^2+3x-4/2x^2-5x+3, 2. 1+3x+5x^(2)+7x^(3)+, simplify x^2+3x-4/2x^2-5x+3,
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